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Assume the acceleration of the object is a(t) = −9.8 meters per second per second (Neglect air resistance.) A baseball is thrown upward from a height of 3 meters with an initial velocity of 7 meters per second. Determine its maximum height. (Round your answer to two decimal places.)

Sagot :

ashish4112119

Answer:

height = 5.682 meters

Step-by-step explanation:

height = -9.8x^2 + 7x + 3

Find the axis of symmetry: x = -b/(2a)

a = -9.8 b = 7 c = 3

x = -7/(2*-9.8) = -7/-19.6 = .357 = x = +.357 secs is when max height occurs

Find the height, replace x with .561

height = -9.8(.357^2) + 11(.357) + 3

height = -9.8(.127) + 11(.357) + 3

height = -1.245+3.927+3

height = 5.682

https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.292302.html

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