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[tex]\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}[/tex]
Solve x²-5x+6
[tex]\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}[/tex]
(x-2)(x-3)
[tex]\blue{\textsf{\textbf{\underline{\underline{How\:to\:Solve:-}}}}[/tex]
First, we think of two numbers such that
If we multiply them, we'll get 6
If we add them, we'll get -5
These numbers are -2 and -3.
Write them here:
(x-2)(x-3)
Now, how do we get (x-2)(x-3) from x(x-2)-3(x-2)?
Notice that (x-2) is the common term, so we factor it out:
(x-2)
And now, we write the other two terms that are left in the parentheses:
(And the terms left are x and -3)
(x-2)(x-3)
Notice that we ended up with the same answer.
Good luck.
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