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Sagot :
The volume of the coffee in each tank will be 1760. in³. The mass of cold coffee and hot coffee will be 6163.29 oz and 10213.45 oz. Then the number of the tank placed on a table is one only.
How to find the density and volume?
She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width of 8.75 inches, a length of 8.75 inches, and a height of 23 inches.
The hot coffee has a density of 5.8 oz/in³ and the cold coffee has a density of 3.5 oz/ in³.
Then the volume of the coffee in each tank will be
We know that the dimension of both tanks is equal. Then the volume will remains equal.
Volume = L × B × H
Volume = 8.75 × 8.75 × 23
Volume = 1760.9375 ≅ 1760.94 in³
Then the mass of the coffee in each the tank will be
The mass of hot coffee will be
Mass = Density × Volume
Mass = 5.8 × 1760.94
Mass = 10213.45 oz
The mass of cold coffee will be
Mass = Density × Volume
Mass = 3.5 × 1760.94
Mass = 6163.29 oz
Then the number of the tank placed on a table is one only.
More about the density and volume link is given below.
https://brainly.com/question/952755
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