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calculate the solubility of in water at . you'll find data in the aleks data tab. round your answer to significant digits.

Sagot :

Lanuel

Based on the calculations, the solubility of PbCrO₄ in water at at 25°C is equal to 1.4 x 10⁻⁸ M.

How to calculate the solubility of PbSO₄?

The properly balanced chemical equation for the dissociation of PbSO₄ is given by:

                         PbCrO₄(s) ⇆ Pb²⁺(aq) + CrO₄²⁻(aq)

Initial                                         0                  0

Change                                   +x                +x

Equib. conc.                             x                  x

Note: The Ksp of PbCrO₄ at 25°C is equal to 2.0 × 10⁻¹⁶.

Next, we would set up an equation from the ICE table for its Ksp;

Ksp = [Pb²⁺][CrO₄²⁻]

2.0 × 10⁻¹⁶ = [x][x]

2.0 × 10⁻¹⁶ = x²

x = √2.0 x 10⁻¹⁶

x = 1.4 x 10⁻⁸ M.

Read more on solubility here: https://brainly.com/question/15396081

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