Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Based on the calculations, the solubility of PbCrO₄ in water at at 25°C is equal to 1.4 x 10⁻⁸ M.
How to calculate the solubility of PbSO₄?
The properly balanced chemical equation for the dissociation of PbSO₄ is given by:
PbCrO₄(s) ⇆ Pb²⁺(aq) + CrO₄²⁻(aq)
Initial 0 0
Change +x +x
Equib. conc. x x
Note: The Ksp of PbCrO₄ at 25°C is equal to 2.0 × 10⁻¹⁶.
Next, we would set up an equation from the ICE table for its Ksp;
Ksp = [Pb²⁺][CrO₄²⁻]
2.0 × 10⁻¹⁶ = [x][x]
2.0 × 10⁻¹⁶ = x²
x = √2.0 x 10⁻¹⁶
x = 1.4 x 10⁻⁸ M.
Read more on solubility here: https://brainly.com/question/15396081
#SPJ1
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.