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[tex]\sf Solve \;it \; with \; steps:-[/tex]
[tex]\bf 3\left(2x+2\right)=\:4x-10[/tex]

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Sagot :

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Answer:

[tex]\boxed{\sf \bold{x = -8}}[/tex]

Explanation:

3(2x+2)= 4x -10

apply distributive method: a(b+c) = ab + ac

3(2x) + 3(2) = 4x - 10

multiply

6x + 6 = 4x - 10

subtract both sides by 4x

6x + 6 - 4x = 4x - 10 -4x

simplify

2x + 6 = -10

subtract both sides by 6

2x + 6 -6 = -10 -6

simplify

2x = -16

divide both sides by 2

x = -8

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex] \textbf{Let's solve :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:3(2x + 2) = 4x - 10[/tex]

[tex]\qquad \sf  \dashrightarrow \:6x + 6 = 4x - 10[/tex]

[tex]\qquad \sf  \dashrightarrow \:6x - 4x = - 10 - 6[/tex]

[tex]\qquad \sf  \dashrightarrow \:2x = - 16[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = - 16 \div 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = - 8[/tex]

[tex] \textsf{Hence, value of x is -8} [/tex]

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