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An electron and a 0.0500-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. Within what lower limit could we determine the position of each object along the direction of the velocity

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onyebuchinnaji

The lower limit that could be used to determine the position of each object along the direction of the velocity is 1.136 x 10⁻³ m.

Uncertainty in the position of the electron

The uncertainty in the position of the electron is calculated as follows;

[tex]\Delta x = \frac{h}{4\pi m\Delta v}[/tex]

where;

  • h is Planck's constant = 6.63 x 10⁻³⁴ Js
  • m is mass of electron
  • Δv uncertainty in velocity = (0.01 x 10⁻²) x 510 = 0.051 m/s

[tex]\Delta x = \frac{6.63 \times 10^{-34} }{4\pi \times 9.11 \times 10^{-31} \times 0.051} \\\\\Delta x = 1.136 \times 10^{-3} \ m[/tex]

Thus, the lower limit that could be used to determine the position of each object along the direction of the velocity is 1.136 x 10⁻³ m.

Learn more about uncertainty in position here: https://brainly.com/question/1970053

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