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Find the solutions of the quadratic equation –9x2 + 49 = 0.

Sagot :

Answer:

x = 7/3

Step-by-step explanation:

Given equation:

  • –9x² + 49 = 0

To determine the value of "x", we need to isolate the x-variable and it's coefficient on one side of the equation. This can be done by subtracting 49 to both sides of the equation.

  • ⇒ –9x² + 49 - 49 = 0 - 49
  • ⇒ –9x² = -49

We can see that the negative sign in on both sides of the equation. Remove it by dividing -1 to both sides of the equation.

  • ⇒ –9x² = -49
  • ⇒ -9x²/-1 = -49/-1
  • ⇒ 9x² = 49

Clearly, we can see that 9x² and 49 are perfect squares. Therefore,

  • ⇒ 9x² = 49
  • ⇒ (3x)² = (7)²

Take square root both sides of the equation:

  • ⇒ √(3x)² = √(7)²
  • ⇒ 3x = 7

To determine the value of "x", we need to isolate it "completely". This can be done by dividing 3 to both sides of the equation

  • ⇒ 3x/3 = 7/3
  • ⇒ x = 7/3

Therefore, the value of "x" must be 7/3.

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