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A 12ft. ladder is leaned against a wall. If the base of the ladder is 5ft. from the wall, how high up on the wall does the ladder reach?​

Sagot :

Answer:

use Pythagoras theorem

[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ \\ a = 5 \\ b = (required \: lenth) \\ c = 12 \\ \\ { {5}^{2} } + {b}^{2} = {12}^{2} \\ {b}^{2} = {12}^{2} - {5}^{2} \\ b = \sqrt{119} \\ b = 10.90871211[/tex]

Pythagorean Theorem

x^2 + 5^2 = 12^2

x^2 +25 = 144

x^2 = 119

x = √199 or 10.9087121146