Answer:
4, -4
Step-by-step explanation:
I think the first equation is ax + 3y = 2, not az + 3y = 2.
ax + 3y = 2
4x + 5y = 6
To use elimination, you need the coefficients of a to either add to zero, or to have a difference of zero if you subtract them.
a + 4 = 0
a = -4
a - 4 = 0
a = 4
Answer: a must be 4 or -4.
Answer:
-4 and 4
Step-by-step explanation:
Given linear system:
[tex]ax+3y=2[/tex]
[tex]4x+5y=6[/tex]
In order to solve the given linear system by elimination without multiplying first, [tex]a[/tex] must be either -4 or 4. That way, when you add or subtract the equations, the variable [tex]x[/tex] will be eliminated.
when [tex]a = -4[/tex]:
[tex]\large\begin{array}{ l r c c l r}& -4x & + & 3y & = & 2\\+ & 4x & + & 5y & = & 6\\\cline{1-6}& & & 8y & = & 8\\\cline{1-6}\end{array}[/tex]
when [tex]a = 4[/tex]:
[tex]\large\begin{array}{ l r c c l r}& 4x & + & 3y & = & 2\\- & 4x & + & 5y & = & 6\\\cline{1-6}& & & -2y & = & -4\\\cline{1-6}\end{array}[/tex]
