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How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.

Sagot :

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula [tex]\displaystyle nCr=\frac{n!}{r!(n-r)!}[/tex] which describes the number of ways we can choose [tex]r[/tex] objects given [tex]n[/tex] possible choices. So, if [tex]n=7[/tex] and [tex]r=4[/tex], then:

[tex]_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35[/tex]

Hence, the teacher can make 35 different geometry quizzes.