The surface area of the regular pyramid is 770 [tex]m^{2}[/tex]
Option B. 770 [tex]m^{2}[/tex] is the answer.
The surface area of a pyramid is a measure of the total area that is occupied by all its faces.
We have to find the surface area of the regular pyramid with a base of 6 sides (hexagonal base).
Surface area of pyramid = area of triangles at the lateral sides + area of base (Hexagon)
Surface area of hexagonal base,
[tex]\frac{1}{2}*(Apothem)*(Perimeter) \\= \frac{1}{2}*(6\sqrt{3} )*(72)\\=216\sqrt{3}[/tex]
Surface area of triangular sides = 6 * 1/2 * b *h
= 3 * 12 *11
= 396 [tex]m^{2}[/tex]
Now total surface area = 216√3 + 396
= 374.112 + 396
= 770.112
≈ 770 [tex]m^{2}[/tex]
The surface area of the regular pyramid is 770 [tex]m^{2}[/tex]
Option B. 770 [tex]m^{2}[/tex]
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