Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
[tex]w=\dfrac{8x^2-2y}{y}[/tex]
Step-by-step explanation:
Question
[tex]\textsf{When}\:\dfrac{2x^2}{y}=\dfrac{w+2}{4}\:\textsf{is solved for}\:w,\:\textsf{one equation is}\:w=\dfrac{8x^2}{y}-2[/tex]
Which of the following is an equivalent to find w?
[tex]w=\dfrac{8x^2+2y}{y}[/tex]
[tex]w=\dfrac{8x^2-2y}{y}[/tex]
[tex]w=8x^2-3y[/tex]
[tex]w=8x^2-y[/tex]
Solution
[tex]\textsf{Given}: \quad w=\dfrac{8x^2}{y}-2[/tex]
[tex]\implies w=\dfrac{8x^2}{y}-\dfrac{2y}{y}[/tex]
[tex]\implies w=\dfrac{8x^2-2y}{y}[/tex]
[tex]\\ \rm\Rrightarrow w=\dfrac{8x^2}{y}-2[/tex]
- Take LCM as y
[tex]\\ \rm\Rrightarrow w=\dfrac{8x^2-2y}{y}[/tex]
Option B is correct
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.