javanelder05
Answered

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find the equation of circle (5,1) diameter 4 square root 5​

Sagot :

semsee45

Answer:

[tex](x-5)^2+(y-1)^2=20[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius)

Given:

  • center = (5, 1)
  • diameter = 4√5

Diameter = 2r (where r is the radius)

⇒ r = 4√5 ÷ 2 = 2√5

Substituting these values into the equation:

[tex]\implies (x-5)^2+(y-1)^2=(2\sqrt{5})^2[/tex]

[tex]\implies (x-5)^2+(y-1)^2=20[/tex]

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