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Sagot :
The amount of CaCO₃ that are consumed at the reaction is 6.7 grams.
What is ideal gas equation?
Ideal gas equation will be represented PV = nRT from which we can calculate the moles of carbon dioxide, where
- P = standard pressure = 1 atm
- V = standard volume = 1500mL = 1.5L
- T = standard temperature = 273 K
- R = universal gas constant = 0.082 L.atm/K.mol
On putting all these values, we get
n = (1)(1.5) / (0.082)(273) = 0.0669 moles = 0.067 mol
Given chemical equation is:
CaCO₃ + 2HCl → CO₂ + CaCl₂ + H₂O
From the stoichiometry of the reaction it is clear that,
1 moles of CO₂ = produced by 1 moles of CaCO₃
0.067 moles of CO₂ = produced by 0.067 moles of CaCO₃
Now mass of CaCO₃ will be calculated as:
n = W/M, where
- n = moles = 0.067mol
- W = required mass = ?
- M = molar mass = 100g/mol
W = (0.067)(100) = 6.7g
Hence required mass of CaCO₃ is 6.7g.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/24236411
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