Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The amount of CaCO₃ that are consumed at the reaction is 6.7 grams.
What is ideal gas equation?
Ideal gas equation will be represented PV = nRT from which we can calculate the moles of carbon dioxide, where
- P = standard pressure = 1 atm
- V = standard volume = 1500mL = 1.5L
- T = standard temperature = 273 K
- R = universal gas constant = 0.082 L.atm/K.mol
On putting all these values, we get
n = (1)(1.5) / (0.082)(273) = 0.0669 moles = 0.067 mol
Given chemical equation is:
CaCO₃ + 2HCl → CO₂ + CaCl₂ + H₂O
From the stoichiometry of the reaction it is clear that,
1 moles of CO₂ = produced by 1 moles of CaCO₃
0.067 moles of CO₂ = produced by 0.067 moles of CaCO₃
Now mass of CaCO₃ will be calculated as:
n = W/M, where
- n = moles = 0.067mol
- W = required mass = ?
- M = molar mass = 100g/mol
W = (0.067)(100) = 6.7g
Hence required mass of CaCO₃ is 6.7g.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/24236411
#SPJ1
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
