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Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The 200 students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a​ professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The students in group 1 had a mean score of with a standard deviation of ​, while the students in group 2 had a mean score of with a standard deviation of . Complete parts ​(a) and ​(b) below.

Two Researchers Conducted A Study In Which Two Groups Of Students Were Asked To Answer 42 Trivia Questions From A Board Game The 200 Students In Group 1 Were As class=

Sagot :

Lower bound is : 2.70 and upper bound is 3.30

a)There is a 90% probability that the difference of the means is in the interval

b) Since the 90% confidence interval does not contain zero, the results suggest that priming does have an effect on scores.

What is Critical Value?

Critical values are essentially cut-off values that define regions where the test statistic is unlikely to lie; for example, a region where the critical value is exceeded with probability if the null hypothesis is true.

Given that:

a) [tex]n_1[/tex]=200, [tex]x_1[/tex]=23.9, [tex]s_1[/tex]=4.7

   [tex]n_2[/tex]=200, [tex]x_2[/tex]=18.8, [tex]s_2[/tex]=4.5

 

The (1-α )% confidence interval for the difference between two mean is:

CI= [tex]x_1-x_2\pm\; t_\frac{\alpha }{2},(n_1+n_2-2\sqrt{\frac{s_1^{2}}{n_1}+\frac{s_2^{2}}{n_2} }[/tex]

the Critical value of 't' will be:

α/2=0.05/2=0.025

Degrees of freedom = [tex]n_1+n_2\\[/tex]-2= 200=200-2=398

[tex]t_{\alpha /2,_(n_1+n_2-2)}= t_{0.025,398}[/tex]=1.96

CI=23.9-18.8±1.96 [tex]\sqrt{\frac{4.7^{2}}{200}+\frac{4.5^{2}}{200} }[/tex]

   = 3±0.3089

   = (3.3089,2.6911)

   ≈(3.30, 2.70)

Thus, 90% confidence interval (3.30, 2.70) implies that the true mean difference value is contained in the interval with probability 0.90.

The Lower bound is : 2.70 and upper bound is 3.30

Thus, There is a 90% probability that the difference of the means is in the interval.

b)The difference between means, null value is 0.

As the null value is 0 and not in the interval, which shows that there is a difference between the two means, concluding that priming does have an effect on scores.

Hence,  Since the 90% confidence interval does not contain zero, the results suggest that priming does have an effect on scores.

Learn more about this concept here:

https://brainly.com/question/16089384

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