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In the figure below,ABC is an isosceles triangle with |AB|=|AC|.|BC| is extended to D such that |AC|=|CD|.If ​

Sagot :

The perimeter of the triangle ABC is [tex]10+\sqrt{10}[/tex] [tex]units[/tex].

The given parameters:

  • Triangle ABC = Isosceles triangle

The length of AC = 3-(-2) = 5 unit

The length of AC = length of BC = 5 unit

The length of BC is calculated by applying Pythagoras theorem as follows;

[tex]BC^2=(4-1)^2+(3-2)^2[/tex]

[tex]BC^2=3^2+1^2[/tex]

[tex]BC^2=10[/tex]

[tex]BC=\sqrt{10}[/tex]

The perimeter of the triangle ABC is calculated as follows;

[tex]P=AB+AC+BC[/tex]

[tex]P=5+5+\sqrt{10}[/tex]

[tex]P=10+\sqrt{10[/tex]  [tex]units[/tex]

Learn more about perimeter of triangle here:

https://brainly.com/question/24382052

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