Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

1. How many formula units are contained in 270.2 g of zinc nitrate, Zn(NO3)2?
50 POINTS

Sagot :

yomamaonmysloppyjoe

Zinc nitrate has 1 molecule of zinc (Zn), 2 molecules of nitrogen (N) and 6 molecules of oxygen (O).

Calculate the molecular mass of zinc nitrate by adding the molecular weights for all molecules in the compound.

Here are the molecular weights for each element:

Zn=65.38 g/mol

N=14.01 g/mol

O=16.00 g/mol

The molecular weight of zinc nitrate is then: 1*(65.38)+2*(14.01)+6*(16.00)=189.40 g/mol.

Using a conversion formula to calculate moles of zinc nitrate:

163.97gZn(NO

3

​

)

2

​

∗

189.40gZn(NO

3

​

)

2

​

1molZn(NO

3

​

)

2

​

​

=0.866molZn(NO

3

​

)

2

​

 

There are 0.866 moles of zinc nitrate.

Note: These numbers may vary slightly due to the source of the molecular weight data and the number of decimal places used.
8.588 x 10^23 formula units
View image Atoro8150
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.