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Sagot :
Step-by-step explanation:
Answer is case 1st:
P(of white button) = 9/13
P(of black button) = 4/12
Case 2nd
P(of black button) = 4/13
P(of white button) = 9/12
Explanation
Given: A Question
To find: Probability
Solution :Case 1st
If carol takes the first button is white
P(of picking a white button) = 9/13
And
P(of picking a black button) = 4/12
Case 2nd
If carol takes the first button is black
So, P(of picking a black button) = 4/13
And P( of picking a white button) = 9/12
Answer is Case 1st
P(of white button) = 9/13
P(of black button) = 4/12
Case 2nd
P(of black button) = 4/13
P(of white button) = 9/12
Explanation: Given : A Question
To find : Probability
Solution : Case 1st
If carol takes the first button is white
P(of picking a white button) = 9/13
And
P(of picking a black button) = 4/12
Case 2nd
If carol takes the first button is black
So, P(of picking a black button) = 4/13
And P(of picking a white button) = 9/12
I hope this helps.
P(of white button) = 9/13
P(of black button) = 4/12
Case 2nd
P(of black button) = 4/13
P(of white button) = 9/12
Explanation: Given : A Question
To find : Probability
Solution : Case 1st
If carol takes the first button is white
P(of picking a white button) = 9/13
And
P(of picking a black button) = 4/12
Case 2nd
If carol takes the first button is black
So, P(of picking a black button) = 4/13
And P(of picking a white button) = 9/12
I hope this helps.
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