Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
a. (40%^5)=0.4^5=0.01024, which is 1.024%
b. the probability that he turns is light off is the probability that he doesn't turn his light on, which is 1-0.4=0.6.
0.6^5=0.07776, or 7.776%
c. 1-0.07776=0.92224, or 92.224%
Answer:
a. 40% = 0.4 → (0.4)⁵ = 0.01024.. ≈ 1.02%.
b. (1 - 0.4) → (0.6)⁵ = 0.07776.. ≈ 7.78%
c. (0.4)¹ → 0.4 = 40%
Explanation:
decimal × 100% = percent.
Since these independent events either occur or do not occur, we can use binomial distribution to determine the theoretical probability of either outcome with a given number of successes or failures (total - successes) or by probability → 1 - success probability = failure probability.
Since the problem is either looking for all or none, we can narrow n! / (n - x)!x! p^x q^n-x down to (probability)^(days). All the rest cancels out.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.