indioscharm
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Sagot :

facundo3141592

By evaluating, we will see that for x = 7 h(x) exceeds g(x).

For which value of x does h(x) first exceed g(x)?

We have:

h(x) = 2*(2)^x

g(x) = 22x - 4

Now we can evaluate both function in the different options:

h(5) = 2*(2)^5 = 64

g(5) = 22*5 - 4 = 106

We can see that for x = 5, h(x) does not exceed g(x), let's try the next one.

h(6) = 2*(2)^6 = 128

g(6) = 22*6 - 4 = 128

So, for x = 6 both functions have the same output, then for x = 7 we will see that h(x) exceeds g(x).

The correct option is B.

If you want to learn more about functions:

https://brainly.com/question/4025726

#SPJ1

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