Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Using the relation between velocity, distance and time, it is found that the velocity of the helicopter is of 225 mph and of the wind is of 69 mph.
What is the relation between velocity, distance and time?
Velocity is given by distance divided by time, that is:
[tex]v = \frac{d}{t}[/tex]
A helicopter took 39 minutes to fly 191 miles, traveling in a headwind. Due to the headwind, the relative velocity is the sum of the velocities, hence:
[tex]v_h + v_w = \frac{191}{\frac{39}{60}}[/tex]
[tex]v_h + v_w = 294[/tex]
[tex]v_w = 294 - v_h[/tex]
The same helicopter took one hour and 15 minutes to fly 195 miles flying in the opposite direction, hence:
[tex]v_h - v_w = \frac{195}{\frac{75}{60}}[/tex]
[tex]v_h - v_w = 156[/tex]
Since [tex]v_w = 294 - v_h[/tex]:
[tex]v_h - 294 + v_h = 156[/tex]
[tex]2v_h = 450[/tex]
[tex]v_h = 225[/tex]
[tex]v_w = 294 - 225 = 69[/tex]
More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569
#SPJ1
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
