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Sagot :
Using the relation between velocity, distance and time, it is found that the velocity of the helicopter is of 225 mph and of the wind is of 69 mph.
What is the relation between velocity, distance and time?
Velocity is given by distance divided by time, that is:
[tex]v = \frac{d}{t}[/tex]
A helicopter took 39 minutes to fly 191 miles, traveling in a headwind. Due to the headwind, the relative velocity is the sum of the velocities, hence:
[tex]v_h + v_w = \frac{191}{\frac{39}{60}}[/tex]
[tex]v_h + v_w = 294[/tex]
[tex]v_w = 294 - v_h[/tex]
The same helicopter took one hour and 15 minutes to fly 195 miles flying in the opposite direction, hence:
[tex]v_h - v_w = \frac{195}{\frac{75}{60}}[/tex]
[tex]v_h - v_w = 156[/tex]
Since [tex]v_w = 294 - v_h[/tex]:
[tex]v_h - 294 + v_h = 156[/tex]
[tex]2v_h = 450[/tex]
[tex]v_h = 225[/tex]
[tex]v_w = 294 - 225 = 69[/tex]
More can be learned about the relation between velocity, distance and time at https://brainly.com/question/24316569
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