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What is the axis of symmetry of h(x) = 6x2 − 60x 147? x = −5 x = −3 x = 3 x = 5

Sagot :

MrRoyal

The function h(x) =  6x² - 60x + 147 is a quadratic function, and the axis of symmetry of the function is x = 5

How to determine the axis of symmetry?

The equation of the function is given as:

h(x) =  6x² - 60x + 147

Differentiate the function

h'(x) = 12x - 60

Set the function to 0

12x - 60 = 0

Add 60 to both sides

12x = 60

Divide both sides by 12

x = 5

Hence, the axis of symmetry of the function is x = 5

Read more about axis of symmetry at:

https://brainly.com/question/15709421

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vexent37

Answer:

X = 5 is correct

Step-by-step explanation:

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