The value of d at the point of equilibrium, to the nearest whole number is 54
How to determine the value of d at equilibrium?
The equations are given as:
[tex]d = \frac{-5}{9}p + 94[/tex]
[tex]s = 3p - 160[/tex]
At the point of equilibrium, d = s.
So, we have:
[tex]\frac{-5}{9}p + 94 = 3p - 160[/tex]
Multiply through by 9
-5p + 846 = 27p - 1440
Collect like terms
27p + 5p = 1440 + 846
Evaluate the sum
32p = 2286
Divide through by 32
p = 71.4375
Substitute p = 71.4375 in [tex]d = \frac{-5}{9}p + 94[/tex]
[tex]d = \frac{-5}{9} * 71.4375 + 94[/tex]
Evaluate
d = 54.3125
Approximate
d = 54
Hence, the value of d at the point of equilibrium, to the nearest whole number is 54
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