Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The quadratic equation with the given characteristics is:
f(x) = (x + 3)*(x - 7).
How to get the quadratic equation?
We know that the vertex must be (2, -25) and it passes through (7, 0).
For a quadratic equation:
y = a*x^2 + b*x +c
The x-value of the vertex is:
x = -b/2a
Then we have:
2 = -b/2a
We also have:
-25 = a*4 + b*2 + c
And because the function passes through (7, 0) we know that 7 is one of the roots, then:
0 = a*49 + b*7 + c
Then we have 3 equations to work with:
2 = -b/2a
-25 = a*4 + b*2 + c
0 = a*49 + b*7 + c
If we subtract the third and second equations we get:
25 = a*45 + b*5
Now, with the first equation we can rewrite:
a = -b/4
Replacing that in the other equation:
25 = a*45 + b*5
25 = (-b/4)*45 + b*5 = b*(-25/4)
25*(-4/25) =b = -4
Now we know the value of b.
2 = -(-4)/2a
a = 1
Now we need to find the value of c, we have that:
0 = 1*49 + -4*7 + c
0 = 49 - 28 + c
0 = 21 + c
Then c = -21
The equation is:
[tex]y = x^2 - 4x - 21[/tex]
It can be factorized to:
f(x) = (x + 3)*(x - 7).
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
#SPJ4
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.