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During a car accident, a 125 kg driver is moving at 31 m/s and in 1.5 seconds is brought to rest by an inflating air bag. what is the magnitude of the change in momentum of the driver? 4.0 kg • meters per second 21 kg • meters per second 47 kg • meters per second 3900 kg • meters per second

Sagot :

nuhulawal20

The magnitude of the change in momentum of the driver is 3900kgm/s.

Hence option D) 3900 kg • meters per second is the correct answer.

What is Momentum?

Momentum is simply the product of the mass of an object and its velocity.

Its is expressed as;

P = m × v

Where m is the mass of the object and v is its velocity.

Given the data in the question;

  • Mass of the driver m = 125kg
  • Velocity v = 31m/s
  • Time elapsed t = 1.5s

We substitute the given values into the expression above to determine the initial momentum of the driver before he was brought to rest.

P initial = m × v

P initial = 125kg × 31m/s

P initial = 3875 kgm/s ≈ 3900kgm/s

Now, as the driver is brought to rest, final velocity becomes zero

P final = 125kg × 0

P final = 0

This means that the change in momentum of the driver is his initial momentum which is 3900kgm/s.

Therefore, the magnitude of the change in momentum of the driver is 3900kgm/s.

Hence option D) 3900 kg • meters per second is the correct answer.

Learn more about momentum here: brainly.com/question/14952164

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keepinthefaith42

Answer:

D for edge

Explanation:

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