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Sagot :
The game is an illustration of probability, and the probability that each player wins is 1/12
How to determine the probability of winning?
From the question, we have the following parameters:
Number of a pair of numbers = 3
A die has 6 possible outcomes.
So, the probability of getting the first pair is:
P1 = 1/6
The probability of getting the second pair is:
P2 = 1/6
The probability of getting the first and the second pairs is
P = 1/6 * 1/6
Evaluate
P = 1/36
There are three pairs of numbers in total.
So, the probability of winning is:
P(Win) = 3 * 1/36
Evaluate
P(Win) = 1/12
Hence, the probability that each player wins is 1/12
Read more about probability at:
https://brainly.com/question/3142228
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Answer:
1/12.
Step-by-step explanation:
The probability that each player has of winning is 1/12.
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