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a sample of krypton gas occupies 75.0 ml at 0.40 atm. if the temperature remained constant, what volume would the krypton occupy at 2.00 atm?

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nuhulawal20

At constant temperature, if the pressure of the sample of the  krypton gas increases to the given value, the volume decreases to 15mL.

What is Boyle's law?

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question question;

  • Initial volume of the gas V₁ = 75.0mL = 0.075L
  • Initial pressure of the gas P₁ = 0.40atm
  • Final pressure of the gas P₂ = 2.00atm
  • Final volume of the gas V₂ = ?

Now, we substitute our given values into the expression above to determine the new volume of the krypton gas.

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 0.40atm × 0.075L / 2.00atm

V₂ = 0.03Latm / 2.00atm

V₂ = 0.015L

V₂ = 15mL

Therefore, at constant temperature, if the pressure of the sample of the  krypton gas increases to the given value, the volume decreases to 15mL.

Learn more about Boyle's law here: brainly.com/question/1437490

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