Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

calculate the ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature.

Sagot :

The ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature is 0.045.

What is speed?

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

[tex]\rm v = \sqrt{\dfrac{3RT}{M}}[/tex]

where R is the universal gas constant and M is the molar mass.

Then the ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature.

The molar mass of nitrogen will be

N₂ = 14 × 2 = 28

The molar mass of carbon dioxide will be

CO₂ = 12 + 16 × 2 = 44

Then we have

[tex]\rm \dfrac{v_{N_2}}{v_{CO_2}} = \dfrac{\sqrt{\frac{3RT}{28}}}{\sqrt{\frac{3RT}{44}}}\\\\\\\dfrac{v_{N_2}}{v_{CO_2}} = \sqrt{\dfrac{44}{28}}\\\\\\\dfrac{v_{N_2}}{v_{CO_2}} = 0.04477 \approx 0.045[/tex]

More about the speed link is given below.

https://brainly.com/question/7359669

#SPJ1

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.