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calculate the ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature.

Sagot :

The ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature is 0.045.

What is speed?

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

[tex]\rm v = \sqrt{\dfrac{3RT}{M}}[/tex]

where R is the universal gas constant and M is the molar mass.

Then the ratio of the velocity of molecular nitrogen gas to the velocity of carbon dioxide gas at the same temperature.

The molar mass of nitrogen will be

N₂ = 14 × 2 = 28

The molar mass of carbon dioxide will be

CO₂ = 12 + 16 × 2 = 44

Then we have

[tex]\rm \dfrac{v_{N_2}}{v_{CO_2}} = \dfrac{\sqrt{\frac{3RT}{28}}}{\sqrt{\frac{3RT}{44}}}\\\\\\\dfrac{v_{N_2}}{v_{CO_2}} = \sqrt{\dfrac{44}{28}}\\\\\\\dfrac{v_{N_2}}{v_{CO_2}} = 0.04477 \approx 0.045[/tex]

More about the speed link is given below.

https://brainly.com/question/7359669

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