Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Using the combination formula, it is found that there is a 0.7778 = 77.78% probability of choosing at least one even number.
What is the combination formula?
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, there are 10 numbers numbered from 1 to 10.
The total number of outcomes is given by:
[tex]T = C_{10,2} = \frac{10!}{2!8!} = 45[/tex]
The number of outcomes with only odd numbers is given by:
[tex]O = C_{5,2} = \frac{5!}{2!3!} = 10[/tex]
Hence 45 - 10 = 35 outcomes have at least one even number, so the probability is:
p = 35/45 = 0.7778.
More can be learned about the combination formula at https://brainly.com/question/25821700
#SPJ1
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.