marwaalqadhi9
Answered

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3. Find the perimeter of the rectangle with length 97 inches and width 17 inches.
228 in.
211 in.
1,649 in.
114 in.

Sagot :

adoran2004
228 in, you times the 97 twice and 17 twice and add together
SeraphicCirce

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[tex]\large{ \underline{ \boxed{ \sf{✰\: Important\: points }}}}[/tex]

➣ Rectangle = A quadrilateral having opposing sides parallel and four right angles.

➣ Length of rectangle = 97inche

➣ Width ( breadth ) of rectangle = 17inche

[tex]\large{ \underline{ \boxed{ \sf{➪\:Perimeter\:rectangle }}}}[/tex]

[tex]\color{pink}{ \boxed{ \sf{☆ \: 2(length \times breadth)}}}[/tex]

[tex]\large{ \underline{ \boxed{ \sf{✰\: Let's \: solve }}}}[/tex]

[tex]\pink{\sf{⇝ p=\: 2(97 + 17)}} \\ \\ {\sf{⇝p= \: 2(114)}} \\ \\ \sf \: ⇝p= 228in.[/tex]

Hence perimeter of the rectangle is 228inch.

Hope it helps ~

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