Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Find the Volume and Surface area

Find The Volume And Surface Area class=

Sagot :

Answer:

Volume: 203,594

Surface Area: 105,237

----------------------------------------------------------------------------------------------------------

Solve for surface area ✅

Let's start with surface area because it is a bit complex.

[tex]A = 5 ah + \frac{1}{2} \sqrt{5(5 + 2 \sqrt{5})}~a^2[/tex]

Now, we must break all of these factors into an equation.

remember, the height is 4, the base is 172

[tex]A = 5 * 172 * 4 + \frac{1}{2} * \sqrt{5 * (5 + 2 * \sqrt{5})} * 172^2[/tex]

[tex]A = \sf 1.05237 * 10^5 = 105,237[/tex]

So that should wrap things up for surface area, being 105,237

________________________________________________________

Solve for volume ✅

Now, we move on to the volume of this pentagonal prism.

[tex]A = \frac{1}{4} \sqrt{5(5 + 2 \sqrt{5})}~a^2h[/tex]

Similar to surface area, but different.

[tex]A = \frac{1}{4} * \sqrt{5 * (5 + 2 * \sqrt{5})} * 172^2 * 4[/tex]

And the result of this is...

[tex]A = \sf 2.03594 * 10^5[/tex]

Which is also equal to ⇒ 203,594

please let me know if this helped or was correct, I really spent a lot of time on this and would like to hear any good or bad feedback. Thanks!

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.