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A lab technician added 2.5 L of water to 0.5 L of
8.50 M solution. What is the new molar
concentration (M) of the diluted solution?


Sagot :

The new molar concentration (M) of the diluted solution when added 2.5L of water to 0.5 L of 8.50 M solution is 1.42M.

How do we calculate the molar concentration of solution?

Molar concentration of the solution will be calculated by using the below equation:
M₁V₁ = M₂V₂, where

M₁ = initial concentration of solution = 8.50 M

V₁ = initial volume = 0.5 L

M₂ = final concentration of diluted solution = ?

V₂ = final volume of diluted solution = 0.5 + 2.5 = 3 L

On putting values, we get

M₂ = (8.50)(0.5) / (3) = 1.416 = 1.42 M

Hence required molar concentration of dilute solution is 1.42M.

To know more about molarity, visit the below link:

https://brainly.com/question/24305514

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