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5y-2x=-3/-4y+x=12 Can someone help me with this system of equation.

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loneguy

[tex]-2x+5y +3=0~~~~~~.....(i)\\\\x-4y -12=0~~~~~~,,,,(ii)\\\\\\~~~~~~~~\dfrac{x}{5(-12)-3(-4)} = \dfrac{y}{3\cdot 1 -(-2)(-12)}=\dfrac{1}{(-2)(-4)-5\cdot 1} \\\\\\\implies \dfrac{x}{-60+12}= \dfrac{y}{3-24} = \dfrac1{8-5}\\\\\\\implies -\dfrac{x}{48}=-\dfrac y{21} = \dfrac 1{3}\\\\\\\implies x = -\dfrac{48}{3},~~~ y = -\dfrac{21}{3}\\\\\\\implies x = -16, ~~~~ y = -7[/tex]

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