Answered

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1) x2 + 5x + 4 = 0
a =
b=
C =
vb2 - 4ac =
-

1 X2 5x 4 0 A B C Vb2 4ac class=

Sagot :

loneguy

[tex]\text{Compare}~ x^2 +5x +4=0~ \text{with the standard form of quadratic equation}~ \\\\ax^2 +bx +c =0\\\\a=1\\\\b=5\\\\c=4\\\\\sqrt{b^2 -4ac} = \sqrt{5^2 -4 \cdot 1 \cdot 4} = \sqrt{25 -16} = \sqrt{9} =3[/tex]

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