Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A basketball player shoots the ball with an initial velocity of 15.8 ft./sec. at an angle of 43.8° with the horizontal. To the nearest tenth, find the initial horizontal component of the vector that represents the velocity of the ball.

A) 4.4 ft./sec.
B) 10.9 ft./sec.
C) 11.4 ft./sec.
D) 15.2 ft./sec.


A Basketball Player Shoots The Ball With An Initial Velocity Of 158 Ftsec At An Angle Of 438 With The Horizontal To The Nearest Tenth Find The Initial Horizonta class=

Sagot :

The initial horizontal component of the vector which represents the velocity of the ball is; Choice C; 11.4 ft./sec.

What is the horizontal component of the ball's velocity?

It follows from the task content that the velocity vector of the ball has magnitude 15.8 ft./sec. and is at an angle of 43.8° with the horizontal.

On this note, it follows from vector resolution that the horizontal component of the ball's velocity is;

V(x) = V cos 43.8⁰

V(x) = 11.4 ft./sec.

Read more on vector resolution;

https://brainly.com/question/1858958

#SPJ1