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Sagot :
Answer:
13 units
given two points: (−3, −8) and (10, −8)
As the y coordinates are same.
use the method:
|x2| + |x1| where (x1, y1), (x2, y2)
Solve:
|10| + |-3|
10 + 3
13
Answer:
10 units
Step-by-step explanation:
[tex](x_1,y_1)=(-3,-8)[/tex]
[tex](x_2,y_2)=(10,-8)[/tex]
We are supposed to find the length of the line segment with endpoints (−3,8) and (7, 8)
We will use distance formula : [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Substitute the values :
[tex]d=\sqrt{(10+3)^2+(8-8)^2}[/tex]
[tex]d=\sqrt{100}[/tex]
[tex]d=10[/tex]
Hence the length of the line segment with endpoints (−3,8) and (7, 8) is 10 units
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