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What is the molarity of a solution formed by dissolving 55.43 grams of CaF- in 3.87 L of solution?

Sagot :

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Answer:

0.24mol/L

Explanation:

The molarity of a solution is also its Concentration (C)

C = [tex]\frac{Moles(n)}{Volume (V)}[/tex]

mass of CaF = 55.43g

volume = 3.87L

Molar mass of CaF = 58.99g/mol

moles = [tex]\frac{55.43g}{58.99g/mol}[/tex]

          =0.94mol

∴ Concentration = [tex]\frac{0.94mol}{3.87L}[/tex]

                             = 0.24mol/L

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