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Balance this equation:

Al(s) + O2 (g) -> Al2O3 (s)


Sagot :

Mole O2 = 9.10 g/32 g/mol = 0.2844 mol From the balanced equation, the mole ratio of O2 to Al2O3 is 3:2. This means that 3 moles of O2 react with Al to produce 2 moles of Al2O3.