- - - -- - - - - - - - - - - - - - - -- - - - - -- - - - - - - -- - - - - - - -- - - - - --
[tex]\blue{\textsf{\textbf{Question:-}}}[/tex]
What is the equation of the line parallel to y=-5x-9 and contains the point (-3, -3)?
[tex]\blue{\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}[/tex]
First of all, parallel lines have the exact same slope.
So we know the slope of the line:- -5.
(enter -5, It's the number that belongs in the green box)
How about the y-intercept?
Well, since we're given the slope and a point that the line intersects, we can write the line's equation in point-slope form:-
y-y1=m(x-x1)
y-(-3)=-5(x-(-3)
y+3=-5(x+3)
y+3=-5x-15
y=-5x-18
Good luck.
- - - -- - - - - - - - - - - - - - -- - - - - - - - - - - - -- - - - - - - - - - - - - - -- - - - -
