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Sagot :
Answer:This is a "two equations, two unknowns" problem.
First lets find our two equations: Children are C and Adults are A
8.50A + 5.50C = 194.00 . COST EQUATION
A + C = 26 TICKETS EQUATION
based on these numbers substitution is the best method (rather than elimination). Since we need both A and C, it doesnt matter which one we do first.
A = 26-C
substituting in the first equation we get
8.5(26-C) + 5.5C = 194
distribute the 8.5
221-8.5C +5.5C = 194
combine like terms and solve for C
221-3C = 194
3C = 27
C = 9 so we sold 9 childrens tickets
to find the adult we can go back to our original second equation
A + C = 26 TICKETS EQUATION
subbing in 9 for C
we get A = 17
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