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Solve for x in the inequality 11|x + 1| < 44

Sagot :

loneguy

[tex]~~~~~~11|x+1| < 44\\\\\implies |x+1| < \dfrac{44}{11}\\\\\implies |x+1| < 4\\\\\implies x +1 > -4~~~ \text{and}~~~ x+1 < 4\\\\\implies x > -4-1~~~ \text{and}~~~~ x < 4-1\\\\\implies x > -5~~~~~~~~ \text{and}~~~~~ x < 3\\\\\text{Hence,}~~ -5 < x < 3[/tex]

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