cardansashley
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

At 25°C and 1.0 atm, 0.84 g of a gas dissolves in 2.00 L of water. What mass of the gas dissolves
in 1.00 L of water at 25°C and 3.0 atm?

Sagot :

Lanuel

The mass of the gas dissolved in 1.00 L of water at 25°C and 3.0 atm is equal to 1.26 grams.

How to determine the mass of the gas dissolved?

In order to determine the mass of the gas dissolved, we would the calculate the new (final) solubility of this gas by applying this formula:

S₁P₂ = S₂P₁

Making S₂ the subject of formula, we have:

S₂ = (S₁P₂)/P₁

S₂ = (0.42 × 3.0)/1.0

S₂ = 1.26 g/L.

Now, we can determine the mass:

Mass = solubility × volume

Mass = 1.26 × 1.00

Mass = 1.26 grams.

Read more on solubility here: https://brainly.com/question/3006391

#SPJ1

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.