Answered

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Will mark branlyest (Polynomial Functions)
1. Find the zeros: 2x^2 + 12x + 18 = 0
A . {-3}
B .{3}
C .{-9}
D.{-3,3}
2. Find the x-intercepts: 2r^2 = 5r + 3
A. {-1/2,3}
B.{-1/2,-3
C.{1/2,3}
D.{1/2,-3}

Sagot :

Answer:

1. A

2. A

Step-by-step explanation:

Question 1

1 Factor out the common term 2.

2(x^2+6x+9)=0

2 Rewrite x^2+6x+9 in the form a^2+2ab+b^2a, where a=x and b=3.

2(x^2+2(x)(3)+3^2)=0

3 Use Square of Sum: (a+b)^2=a^2+2ab+b^2(a+b).

2(x+3)^2=0

4 Divide both sides by 2.

(x+3)^2=0

5 Take the square root of both sides.

x+3=0

6 Subtract 3 from both sides.

x=-3

Question 2

1 Move all terms to one side.

2r^2-5r-3=0

2 Split the second term in 2r^2-5r-3 into two terms.

2r^2+r-6r-3=0

3 Factor out common terms in the first two terms, then in the last two terms.

r(2r+1)-3(2r+1)=0

4 Factor out the common term 2r+1.

(2r+1)(r-3)=0

5 Solve for r.

r=-1/2,3

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