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Find the surface area of a square pyramid with side length 6 cm and slant height 5
cm.

Sagot :

The surface area of the square pyramid is 96 sq. mi.

Given:

side length (s) = 6 mi

slant height (l) = 5 mi

*image of a typical square pyramid is shown in the attachment below.

Recall:

Formula for surface area of square pyramid (SA) = [tex]A+\frac{1}{2}Pl[/tex]

Where,

[tex]A=[/tex] area of the base = [tex]s^2=6^2=36[/tex] sq mi

[tex]P=[/tex] perimeter of the base = [tex]4(s)=4*6=24[/tex]  mi

[tex]l=[/tex] slant height = 5 mi

Plug in the values

[tex]SA=36+\frac{1}{2} *24*5[/tex]

[tex]SA=36+60[/tex]

[tex]SA=96[/tex]

The surface area(SA) of the square pyramid is 96 sq. mi

Learn more about surface area of a square pyramid here:

https://brainly.com/question/8830629

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