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Solve.
4(x+2)^2=16


HELP PLSSSS

Sagot :

Andrafonia

Answer:

x=0; x=-2

Step-by-step explanation:

so first you do (x+2)^2 which is x^2+2x+4

4x^2 +8x +16 = 16

Subtract 16 from both sides

4x^2 +8x = 0

factor out 4x:

4x(x+2) = 0

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