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Sagot :
Answer:
The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.
Explanation:
Let's use Newton's 2nd Law to help solve this problem.
- F = ma
The force acting on the Ferris wheel is the centripetal force, given in the problem: [tex]F_c=115 \ \text{N}[/tex].
The mass "m" is the sum of the man and woman's masses: [tex]85+65= 150 \ \text{kg}[/tex].
The acceleration is the centripetal acceleration of the Ferris wheel: [tex]a_c=\displaystyle \frac{v^2}{r}[/tex].
Let's write an equation and solve for "v", the tangential (linear) acceleration.
- [tex]\displaystyle 115=m(\frac{v^2}{r} )[/tex]
- [tex]\displaystyle 115 = (85+65)(\frac{v^2}{20})[/tex]
- [tex]\displaystyle 115=150(\frac{v^2}{20} )[/tex]
- [tex].766667=\displaystyle(\frac{v^2}{20} )[/tex]
- [tex]15.\overline{3}=v^2[/tex]
- [tex]v=3.9158[/tex]
The Ferris wheel's tangential velocity is 3.92 m/s.
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