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Sagot :
Answer:
- Current = 0.33 A
Explanation:
- For diagram refer the attachment.
It is given that five cells of 2V are connected in series, so total voltage of the battery:
[tex]\dashrightarrow \: \: \sf V = 2 \times 5 = 10 V [/tex]
Three resistor of 5[tex]\Omega[/tex], 10[tex]\Omega[/tex], 15[tex]\Omega[/tex] are connected in Series, so the net resistance:
[tex]\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}[/tex]
[tex]\dashrightarrow \: \: \sf R = 5 + 10 + 15 [/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \: \Omega}}}}[/tex]
According to ohm's law:
[tex]\dashrightarrow \sf\: \: V = IR [/tex]
[tex]\dashrightarrow \sf \: \: I = \dfrac{V}{R}[/tex]
On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 [tex]{\pmb{\sf{\Omega}}}[/tex] we get:
[tex]\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}[/tex]
[tex]{ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}[/tex]
[tex]\therefore[/tex]The electric current passing through the above circuit when the key is closed will be 0.33 A
Answer:
Resistance = 5 + 10 + 15 = 30
Explanation:
Current= 0.33 Amperes
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