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Consider the series 4 + 12 + 36 ... Find the sum of the first 9 terms.​

Sagot :

Answer:

39364

Step-by-step explanation:

You can simplify the equation to make 4(1+3+9...) The nth term is therefore [tex]3^{n-1}[/tex] so u can substitute that into the equation so 4([tex]3^{n-1}+ 3^{n} + 3^{n+1}[/tex]..). This would simplify to 4([tex]3^0 +3+3^2[/tex]+[tex]3^3+3^4+3^5+3^6+3^7+3^8[/tex]). By simplifying this, you can make it so 4([tex]2^2+6^2+18^2+42^2+81^2[/tex]) = 4(4+36+324+2916+6561) =39364

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