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Cone A is divided into Cone B and Frustum C. B A 12cm C 20cm 20cm Express the volume of Frustum C as a fraction of the volume of Cone A. Give your answer in its simplest form.​

Cone A Is Divided Into Cone B And Frustum C B A 12cm C 20cm 20cm Express The Volume Of Frustum C As A Fraction Of The Volume Of Cone A Give Your Answer In Its S class=

Sagot :

The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³

Calculation of a frustum

The volume of cone A V=πr²h/3

Where radius = 20cm

The volume of cone B = V=πr²h/3

Where radius = 12cm

Therefore volume of frustum =

V=π * 20² * h/3 - π * 12² *h/3

The variables will cancel out each other

V = 20² - 12²

V = 400- 144

V = 256cm³

Therefore, the volume of the frustum(C) = 256cm³

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