Answered

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2x2 – 9x + 2 = –1
The discriminant is less than 0, so there are two real roots.
The discriminant is less than 0, so there are two complex roots.
The discriminant is greater than 0, so there are two real roots.
The discriminant is greater than 0, so there are two complex roots.

Sagot :

semsee45

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

Discriminant

[tex]b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}[/tex]

[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}[/tex]

[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}[/tex]

[tex]2x^2-9x+2=-1[/tex]

[tex]\implies 2x^2-9x+3=0[/tex]

[tex]\implies a=2, b=-9, c=3[/tex]

[tex]\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}[/tex]

Answer:

C on edge

Step-by-step explanation:

took the test lol

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